godet: get main status code

Hi. I tried to get status code of the requested url with a code like this:

...
remote.CallbackEvent("Network.responseReceived", func(params godet.Params) {
	resp := params.Map("response")
	url = resp["url"].(string)
	statusCode = int(resp["status"].(float64))
	fmt.Println(statusCode, url)
})
tab, err := remote.NewTab("https://www.somewhere.com")
...

but when I run it, i get this:

200 https://www.somewhere.com/Content/css?v=nzhr89jyV 
200 https:/www.somewhere.com/bundles/angularjs?v=7xwsovO
200 https://www.somewhere.com/bundles/js?v=C3adeImoIV 
200 https://www.somewhere.com/bundles/app?v=vp6dm1p3JfVY  
200 https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js
...

the url https://www.somewhere.com is not returned among them. how can I get the page’s status code?

About this issue

Original URL
State: closed
Created 6 years ago
Comments: 16 (7 by maintainers)

Most upvoted comments

It’s because you are using remote.NewTab(). This will open a new tab with the URL and then connect the debugger to it. In the time it takes the debugger to connect the page will have already loaded a whole bunch of resources for which you missed the events.

You need to use remote.Navigate() to navigate in the currently connected tab. Or you need to create the new tab using remote.NewTab("about:blank") and when that returns use remote.Navigate().

erikdubbelboer on Feb 27, 2018