chain: Swtching from chain to code doesn't do anything.
My intention to do was to switch to code to write a function like:
var function = test() {
}
and I thought, when I switch back to chain, It will parse the code and give me the visual block and vice versa. If so, it doesn’t work, in both directions.
About this issue
- Original URL
- State: closed
- Created 8 years ago
- Comments: 15 (8 by maintainers)
Oh yeah sry, i meaned var test = function()