chain: Swtching from chain to code doesn't do anything.

My intention to do was to switch to code to write a function like:

var function = test() {

}

and I thought, when I switch back to chain, It will parse the code and give me the visual block and vice versa. If so, it doesn’t work, in both directions.

About this issue

  • Original URL
  • State: closed
  • Created 8 years ago
  • Comments: 15 (8 by maintainers)

Most upvoted comments

Oh yeah sry, i meaned var test = function()